Talk:Hiver Calendar

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Revision as of 11:52, 4 June 2008 by Gruffty (talk | contribs) (Slippage)
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OK, I've looked at CT AM7 and the Hiver calendar is totally screwed. The book says Glea rotates about its own axis once in "about 22 hours", a HF year is 143 cycles = 179 standard days. I'm going to have to work this out on a spreadsheet to get this to work. Gruffty Hivers: If you tolerate us, then your children will be next... 13:09, 3 June 2008 (UTC)

The Basics

OK: 1 Hiver day = 22 standard hours (according to CT AM7). On that basis:

  • 11 standard days (of 24 standard hours each) equals 12 Hiver days (of 22 standard hours each) exactly;
  • 264 standard hours (or 11 standard days) equals 12 Hiver days (of 22 standard hours each) exactly.

That's my starting point for sorting Teh Hivorz Kalenda Mesz out. Gruffty Hivers: If you tolerate us, then your children will be next... 13:29, 3 June 2008 (UTC)

The Year

  • A Hiver year = 179 standard days = 4,296 standard hours;
  • 4,296 standard hours divided by 22 standard hours (per Hiver day) = 195.2727 Hiver days (of 22 standard hours each).
  • A Hiver "day" is termed a "cycle" by the Hivers: 1 cycle = 1 day = 22 standard hours.
  • 195.2727 Hiver days/cycles (of 22 standard hours each) = 1 Hiver year = 179 standard days = 4,296 standard hours.

However.... CT AM7 p. 15 states that Glea orbits New Primary every 358 days (i.e. 2 * 179 standard days). Thus the Hivers get 2 years for the price of one. Gruffty Hivers: If you tolerate us, then your children will be next... 13:50, 3 June 2008 (UTC)

Slippage

It looks like Hiver years slip by a year for every 52 standard years. Each standard year = 2 Hiver years + 168 hours (7 standard days). So:

  • 1 standard year = 2 HF years + 1 week
  • 2 standard years = 4 HF years + 2 weeks
  • 3 standard years = 6 HF years + 3 weeks

and so on. Gruffty Hivers: If you tolerate us, then your children will be next... 11:52, 4 June 2008 (UTC)